Shortcut Tricks are very important things in competitive exam. Time takes a huge part in competitive exams. If you know time management then everything will be easier for you. Most of us miss that part. Few examples on average shortcuts is given in this page below. We try to provide all types of shortcut tricks on average here. We request all visitors to read all examples carefully. These examples here will help you to better understand shortcut tricks on average.
Now we will discuss some basic ideas of Average Methods. On the basis of these ideas we will learn trick and tips of shortcut average methods. If you think that how to solve average methods questions using average methods shortcut tricks, then further studies will help you to do so.
What is Average?
The result obtained by adding several quantities together and then dividing this total by the number of quantities is called Average. The main term of average is equal sharing of a value among all, where it may share persons or things. We obtain the average of a number using formula that is sum of observations divide by Number of observations.
Here is average based some fact and formula and some average shortcut tricks examples. The problem are given in Quantitative Aptitude which is a very essential paper in banking exam. Under below given some more example for your better practice.
Anything we learn in our school days was basics and that is well enough for passing our school exams. Now the time has come to learn for our competitive exams. For this we need our basics but also we have to learn something new. That’s where shortcut tricks are comes into action.
Formula:
- Average: = ( Sum of observations / Number of observations ).
Find the Average Speed
Suppose Rahul covers a certain distance at P Kmph and an equal distance at O Kmph. Then,
the average speed during the whole journey is (2PO / P + O ) Kmph.
Find the Average of all numbers ?
There are Five Numbers, we are going to calculate the average of 29, 31, 33, 37, 49.
Average = (29 + 31 + 33 + 37 + 49 ) / 5 = 179 / 5 = 35.8.
Example 1: The average of five positive integers is 55.8 If average of first two integers is 49 and the average of fourth and fifth integers is 69.5 Than find the thired integer.
Answer : Shortcut :
55.8 x 5 = 279
49 x 2 = 98
69.5 x 2 = 139
third number = (279 – 98 – 139) = 42.
Example 2: The average of four numbers is 80. The first number is 1 / 3 of sum of three number. What would be the first number ?
Example : P + Q + R + S = 320 —— (I)
P = Q + R + S / 3 ——(II)
from (I) and (II)
4P = 240
P = 80
Example 3:The average of six numbers is 18, If average of four number is 12. What would be the average of remaining two number ?
Answer : (18 x 6) – (12 x 4) = 108 – 48 = 60
the average of remaining two number 60 / 2 = 30.
Example 4: What would be the average of first 20 natural numbers ?
Answer :
Sum of first n natural numbers = n ( n + 1 ) /2
So, we can find easily average of first 20 natural numbers 20 x 21 / 2 = 210
So, then Required average is = 210 / 20 = 10.5.
Example 5: In a college, 16 girls has the average age is 18 years and 14 boys has the average age 17 years. What would be the average age of entire college ?
Answer: 16 girls has the average age is 18 years ( 16 x 18 ) = 288
4 boys has the average age 17 years ( 14 x 17 ) = 238
Average age is = 288 + 238 / 30 = 526 / 30 = 17.54 years
Example 6: The average of five numbers is 64.6. The average of first and second numbers is 66 and the average of 4th and 5th number is 86. Find the third number.
Answer : 3rd number is = 323 – ( 132 + 172 ) = 323 – 304 = 19.
Example 7: The average salary of 25 employee in a company per month is Rs.6000. If the salary of manager’s is added than the salary is increase is Rs. 6500. What would be the salary of the manager’s ?
Answer : average salary of employee in company is = 6000
when added one member salry 25 + 1 = 26 = 6500.
So, (26 x 6500)-(25 x 6000) = 169000 – 150000 = 19000
Example 8:
What would be the average of first 20 multiplies of 5.
Answer:
Required average = 5 ( 1 + 2 + 3 +……………….. + 20) /20
= ( 5 x 20 x 21 / 20 x 2) = 2100 / 40 = 52.5.
So the Required average is 52.5.
Example 9:
The average marks of 13 students is 40, the first six students is 30 and that of the last six students is 32. Find the value of the 7th number.
Answer :
Shortcut tricks :
7th student marks number = Total of 13 students result – ( Total of first six students + Total of last six students results )
= 13 x 40 – ( 6 x 30 + 6 x 32 )
= 520 – 180 + 192
= 148.
Example 10:
The average of five numbers is 29, if one number is exclude the average becomes 27. what is the exclude number ?
Answer :
let the exclude number is
= ( 29 x 5 ) – ( 27 x 4 )
= 145 – 108
= 37.
The exclude number 37.
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